Use the following form to solve any given triangle. Three inputs are required for the solution. Atleast one of the input needs to be a side of the triangle.
Given: Sides a = 10, b = 10, c = 10
Applying Cosine law on side 'a' we get;
CosA = (b2 + c2 – a2 )/2 · b · c
CosA = 0.5, Or A = 60 degrees
Similarly
CosB = (a2 + c2 – b2 )/2 · a · c
CosB = 0.5, Or B = 60 degrees
Finally
CosC = (a2 + b2 – c2 )/2 · a · b
CosC = 0.5, Or C = 60 degrees
Other math based tools